50道C/C++编程练习题 复习必备(1-10)

1. 输入3个数，求最大值

C

#include<stdio.h> int main() { 
    int a, b, c,m; scanf_s("%d%d%d", &a, &b,&c); m = a; if (b > m) m = b; if (c > m) m = c; printf("max number is %d", m); return 0; } 

C++

#include<iostream> using namespace std; int main() { 
    int a, b, c, m; cin >> a >> b >> c; cout << a << endl; cout << b << endl; cout << "the meaning of c =" << c << endl; m = a; if (b > m) m = b; if (c > m) m = c; cout << m<<endl; }

2. 编程序，求方程ax2+bx+c=0的根

C

#include<stdio.h> #include<math.h> int main() { 
    double a, b, c, d, x1, x2; printf( "请输入一元二次方程a,b,c对应的值，用空格隔开\n"); scanf_s("%5lf%5lf%5lf", &a, &b, &c); printf ( "a=%5lf,b=%5lf,c=%5lf\n",a,b,c); if (a == 0 & b == 0) { 
    printf( "方程无解\n"); return 0; } if (a == 0) { 
    printf("x的值是%5lf\n", -c / b ); return 0; } d = b * b - 4 * a * c; if (d < 0) { 
    printf("方程无解\n"); return 0; } if (d == 0) { 
    x1 = (-b) / (2 * a); printf("x1=x2,他们的值是%5lf\n", x1); return 0; } if (d > 0) { 
    x1 = (-b + sqrt(d)) / (2 * a); x2 = (-b - sqrt(d)) / (2 * a); printf("x1，x2,他们的值是x1=%5lf,x2=%5lf\n", x1,x2); return 0; } } 

C++

#include<iostream> using namespace std; #include<cmath> int main() { 
    double a, b, c,d,x1,x2; cout << "请输入一元二次方程a,b,c对应的值，用空格隔开"<<endl; cin >> a >>b >> c; cout << "a=" << a << ",b=" << b << ",c=" << c << endl; if (a == 0 and b == 0) { 
    cout << "方程无解" << endl; return 0; } if (a == 0) { 
    cout << "x的值是" << -c / b << endl; return 0; } d = b * b - 4 * a*c; if (d<0) { 
    cout << "方程无解" << endl; return 0; } if (d==0) { 
    x1 = (-b) / (2 * a); cout << "x1=x2=" <<x1 << endl; return 0; } if(d>0) { 
    x1 = (-b + sqrt(d)) / (2 * a); x2 = (-b - sqrt(d)) / (2 * a); cout << "x1=" << x1<< ",x2="<<x2 << endl; return 0; } }

3. 输入一个成绩，打印相应的等级

C

#include<stdio.h> int main() { 
    printf("请输入您的成绩，回车结束\n"); int grade; scanf_s("%d", &grade); if (grade >=90) printf("您的等级是A"); else if (grade >= 60) printf("您的等级是B"); else printf("您的等级是C"); }

C++

#include<iostream> using namespace std; int main() { 
    cout << "请输入您的成绩，分数在0-100 之间的整数，回车结束"<<endl; int grade; cin >> grade; if (grade >= 90) cout << "您的等级是A"; else if (grade >= 60) cout << "您的等级是B"; else cout << "您的等级是C"; }

4. 输入3个double类型的值，判断这3个值是否可以表示一个三角形的三条边

C

#include<stdio.h> int main() { 
    double a, b, c; printf( "请输入三角形的三条边，以空格分隔，回车结束\n"); scanf_s("%5lf%5lf%5lf", &a, &b, &c); if ((a + b) > c and (a + c) > b and (b + c) > a) printf( "可以组成三角形"); else printf( "不可以组成三角形"); }

C++

#include<iostream> using namespace std; int main() { 
    double a, b, c; cout << "请输入三角形的三条边，以空格分隔，回车结束"<<endl; cin >> a >> b >> c; if ((a + b) > c and (a + c) > b and (b + c) > a) cout << "可以组成三角形"; else cout << "不可以组成三角形"; }

5. 输入20个数，求其最大、最小和平均值

C

#include<stdio.h> int main() { 
    double total; int minnumber, maxnumber, a; printf( "请输入20个数字，以回车结束" ); scanf_s("%d",&a); total = minnumber = maxnumber = a; for (int i = 1; i < 20; i++) { 
    scanf_s("%d", &a); if (maxnumber < a) { 
    maxnumber = a; } if (minnumber > a) minnumber = a; total = total + a; } printf("最大值是：%d\n",maxnumber); printf("最小值是：%d\n", minnumber); printf("平均值是%3lf",total/20); }

C++

#include<iostream> using namespace std; int main() { 
    double a, minnumber, maxnumber, total; cout << "请输入20个数字，以回车结束" << endl; cin >> a; total = minnumber = maxnumber = a; for(int i=1; i<20;i++) { 
    cin >> a; if (maxnumber<a) { 
    maxnumber = a; } if (minnumber > a) minnumber = a; total = total + a; } cout << "最大值是：" << maxnumber<<endl; cout << "最小值是：" << minnumber << endl; cout << "平均值是：" << total / 20; }

6. 输入若干个数，设输入的第一个数为后面要输入的数的个数，求平均值及最大值

C

#include<stdio.h> int main() { 
    int n, a, maxnumber, minnumber, total; printf("请输入要计算数字的个数 和数字，用空格分开\n"); scanf_s("%d", &n); scanf_s("%d" ,& a); maxnumber = minnumber = total = a; for (int i = 1; i < n; i++) { 
    scanf_s("%d", &a); if (a > maxnumber) maxnumber = a; if (a < minnumber) minnumber = a; total += a; } float d; d = total / n; printf( "平均值为%3lf\n",d); printf("最大值为%d\n", maxnumber); printf("最小值为%d\n", minnumber); }

C++

#include<iostream> using namespace std; int main() { 
    int n, a, maxnumber, minnumber,total; cout << "请输入要计算数字的个数" << endl; cin >> n; cin >> a; maxnumber = minnumber = total = a; for(int i=1;i<n;i++) { 
    cin >> a; if (a > maxnumber) maxnumber = a; if (a < minnumber) minnumber = a; total += a; } cout << "最大值为" << maxnumber << endl; cout << "最小值为" << minnumber << endl; double d; d = total / n; cout << "平均值为" << d<<endl; }

7. 输入若干个数，输入-999表示结束，求平均值及最大值

C

#include<stdio.h> int main() { 
    int a, maxnumber, total; int n = 1; printf( "输入若干个数，输入 -999表示结束" ); scanf_s("%d",&a); maxnumber = a; total = 0; while (a != -999) { 
    if (a > maxnumber) maxnumber = a; total += a; n = n + 1; scanf_s("%d", &a); } printf("最大值为：%d", maxnumber); float d = total / n; printf( "平均值为%3lf",d); return 0; } 

C++`

using namespace std; int main() { 
    int a,maxnumber, total; int n = 1; cout << "输入若干个数，输入 -999表示结束"<<endl; cin >> a; maxnumber = a; total = 0; while(a!=-999) { 
    if (a > maxnumber) maxnumber = a; total += a; cout << "total=" << total << endl; n = n + 1; cin >> a; } cout << "最大值为：" << maxnumber<<endl; cout << "平均值为：" << total / n; return 0; }

8. 求和 s=1X1 + 2X2 + 3X3 +…+ 100X100

C

#include<stdio.h> int main() { 
    int sum = 0, temp; for (int i = 1; i <= 100; i++) { 
    temp = i * i; sum += temp; } printf("1-100平方的和为%d",sum); }

C++

#include<iostream> using namespace std; int main() { 
    int sum=0,temp; for (int i = 1; i <= 100; i++) { 
    temp = i * i; sum += temp; } cout << "1-100平方的和为" << sum; return 0; }

9. 印度国王的奖励，求和 2的0次方加到2的63次方

C

#include<stdio.h> int main() { 
    double sum = 1, temp = 1; for (int i = 1; i < 64; i++) { 
    temp = temp * 2; sum = sum + temp; } printf("%lf", sum); return 0; }

C++

#include<iostream> using namespace std; int main() { 
    double sum = 1,temp=1; for(int i=1;i<64;i++ ) { 
    temp = temp * 2; sum = sum + temp; } cout << sum << endl; return 0; }

10. 求和 s=1! + 2! + 3! +…+ 10!

C

#include<stdio.h> int main() { 
    double sum = 1, temp = 1; for (int i = 1; i < 64; i++) { 
    temp = temp * 2; sum = sum + temp; } printf("%9lf", sum); return 0; }

C++

#include<iostream> using namespace std; int main() { 
    double sum = 1,temp=1; for(int i=1;i<64;i++ ) { 
    temp = temp * 2; sum = sum + temp; } cout << sum << endl; return 0; }

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